2^(2x)-6=1/(2^(x)+8)

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Solution for 2^(2x)-6=1/(2^(x)+8) equation: 



2^(2x)-6=1/(2^(x)+8)

We move all terms to the left:

2^(2x)-6-(1/(2^(x)+8))=0



Domain of the equation: (2^x+8))!=0

x∈R



We multiply all the terms by the denominator


2^2x*(2^x+8))-(1-6*(2^x+8))=0

We multiply parentheses

2^2x*(2^x+8))-(1-12x-=0

We add all the numbers together, and all the variables

-12x+2^2x*(2^x+8))-(1=0

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